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  1. #76
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    Quote Originally Posted by Eric40962005 View Post
    No I’m not wrong heat lol I’m telling you that’s not how you calculate it from 0-60 in distance.



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    Well I just don’t understand then... to me at a certain speed a certain amount of feet are travelled period. So two different times to get to that speed is the time difference which converts into a distance travelled and it’s 8’ per 1/10 of a second. I don’t see how that can be disputed. Doesn’t matter what vehicle it is, any object traveling at 60 mph moves 8 feet per second no matter what.


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  2. #77
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    new tires already almost done now which ones for widebody?

    here buddy im on my computer now i can show you how to calculate it. these calculations are based on linear acceleration.

    Using basic kinematics, D = (V-V0) * t / 2

    where V(Ending speed)=88 ft/s, V0(starting speed) = 0, t = 3.9
    D= (88ft/s-0ft/s)*3.9/2
    and the answer is 171.6 ft.
    Now i will do your 4.4 second 0-60 mph

    D= (88ft/s-0ft/s)*4.4/2

    that answer is 193.6

    that would be 193.6- 171.6 = 22 feet ahead and that a full half second.

    you have to remember you are only traveling at 60 mph for a micro second. So you can’t base distance off of a constant speed.
    Last edited by Eric40962005; 12-05-2019 at 09:58 PM.
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  3. #78
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    Quote Originally Posted by Eric40962005 View Post
    here buddy im on my computer now i can show you how to calculate it. these calculations are based on linear acceleration.

    Using basic kinematics, D = (V-V0) * t / 2

    where V(Ending speed)=88 ft/s, V0(starting speed) = 0, t = 3.9
    D= (88ft/s-0ft/s)*3.9/2
    and the answer is 171.6 ft.
    Now i will do your 4.4 second 0-60 mph

    D= (88ft/s-0ft/s)*4.4/2

    that answer is 193.6

    that would be 193.6- 171.6 = 22 feet ahead and that a full half second.

    you have to remember you are only traveling at 60 mph for a micro second. So you can’t base distance off of a constant speed.
    Man I must have skipped some math days in high school lol. Thank you for this, so at your calculation 1/2 second in a 0-60 race is 22 feet? Which is about a car and half length ahead... guess if that’s right it’s not as significant as I thought.


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  4. #79
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    Quote Originally Posted by Heat00 View Post
    Here is 10.7 vs 12.0, 1.3 seconds and look at the distance they are apart... it’s easily 13 car lengths which supports my theory for the most part. So if 1.3 seconds is about 14 car lengths the. A tenth of a second at 100 mph is a good full car length. While I agree at 60 it’s less feet travelled it’s still a lot more than a fender or inches, I bet it’s close to a car length


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    Joey...0.10 seconds is NOT a full car length...even at the track unless they're running 150+ lol

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  5. #80
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    Now a 1/10th of a second in top fuel is probably 10 car lengths lol


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